20. Convergence of Positive Series

a. Overview

Given a series n=noan\displaystyle \sum_{n=n_o}^\infty a_n, our goal is to find the sum of the series, either exactly (as for the geometric or telescoping series) or approximately (as done at the end of this chapter). To approximate the series, we usually just add up a finite number of terms. Once we do that, we will want to know the error in using a finite number of terms instead of an infinite number of terms. However, before we can even approximate the series, we at least need to know the series has a finite sum, i.e. that it converges. Otherwise, adding up a finite number of terms is a waste of time.

Checking a series for convergence is much like doing an integral. In doing an integral, you must look at the integrand and determine which integration technique to use. In checking a series for convergence, you must look at the terms and decide which convergence test to use. We split the convergence tests into two groups, those for positive series and those for more general series.


A series n=noan\displaystyle \sum_{n=n_o}^\infty a_n is positive if all of its terms are positive, an>0a_n>0 for all nn.
A series n=noan\displaystyle \sum_{n=n_o}^\infty a_n is negative if all of its terms are negative, an<0a_n< 0 for all nn.
A general series is an arbitrary series which is not necessarily positive and not necessarily negative.

Here, we list the Convergence and Divergence Tests for Positive Series along with the necessary definitions. There is no attempt to justify or prove the tests. That will be done later in this chapter. If a series is negative, the tests for positive series will work after an overall minus sign is factored out. At the end of the section, we will come back to approximating the series by a finite number of terms and finding the error in this approximation.

We start with the two tests covered in the previous chapter.

A tail of a series n=noan\displaystyle \sum_{n=n_o}^\infty a_n is any series of the form n=Nan\displaystyle \sum_{n=N}^\infty a_n where N>noN>n_o.

The Tail Test
A series n=noan\displaystyle \sum_{n=n_o}^\infty a_n is convergent if and only if any (and hence every) tail is convergent.

This proposition says the convergence of a series does not depend on any finite number of terms. Further, if the tail is all positive (or all negative) you can apply the tests for positive series to the tail.

Don't forget to apply the nthn^\text{th} Term Divergence Test. Then move on to the other tests.

The nth Term Divergence Test
If limnan0\displaystyle \lim_{n\to\infty}a_n\neq 0, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is divergent.

If limnan=0\displaystyle \lim_{n\to\infty}a_n=0 the nthn^\text{th} Term Divergence Test FAILS and says nothing about n=noan\displaystyle \sum_{n=n_o}^\infty a_n.

The Integral Test
If an=f(n)a_n=f(n) where f(x)f(x) is a continuous, positive, decreasing function on [no,)[n_o,\infty), then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is convergent if and only if nof(x)dx\displaystyle \int_{n_o}^\infty f(x)\,dx is convergent.

In practice, we don't switch from the terms ana_n to the function f(x)f(x). We just regard nn as a continuous variable and ana_n as a continuous function of nn and compute noandn\displaystyle \int_{n_o}^\infty a_n\,dn

As a special case of the integral test we have:

The pp-Series Test
The pp-series n=no1np\displaystyle \sum_{n=n_o}^\infty \dfrac{1}{n^p} is convergent if p>1p \gt 1 and is divergent if p1p \le 1.

The Simple Comparison Test
Suppose n=noan\displaystyle \sum_{n=n_o}^\infty a_n and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n are positive series.

  1. If n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is convergent and anbna_n \le b_n for all nn, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is also convergent.
  2. If n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is divergent and anbn a_n \ge b_n for all nn, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is also divergent.

In applying the simple comparison test, n=noan\displaystyle \sum_{n=n_o}^\infty a_n is the original series while n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is the comparison series whose convergence is already known.

Sometimes we want to compare an original series n=noan\displaystyle \sum_{n=n_o}^\infty a_n to a comparison series n=nobn\displaystyle \sum_{n=n_o}^\infty b_n but we can't prove the necessary inequality. In that case, we should try the limit comparison test:

The Limit Comparison Test
Suppose n=noan\displaystyle \sum_{n=n_o}^\infty a_n and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n are positive series and limnanbn=L\displaystyle \lim_{n\to\infty}\dfrac{a_n}{b_n}=L.

  1. If 0<L<0< L< \infty, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is convergent if and only if n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is convergent.
  2. If L=0L=0 and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is convergent, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is also convergent.
  3. If L=L=\infty and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is divergent, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is also divergent.

Cases (2) and (3) are called the extreme cases, and arise very rarely.
If L=0L=0 and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is divergent, or L=L=\infty and n=nobn\displaystyle \sum_{n=n_o}^\infty b_n is convergent, the Limit Comparison Test FAILS.

The Ratio Test
Suppose n=noan\displaystyle \sum_{n=n_o}^\infty a_n is a positive series and the limit of the ratio of successive terms is ρ=limnan+1an\displaystyle \rho=\lim_{n\to\infty}\dfrac{a_{n+1}}{a_n}.

  1. If ρ<1\rho<1, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is convergent.
  2. If ρ>1\rho>1, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is divergent.

If ρ=1\rho=1 the Ratio Test FAILS and says nothing about n=noan\displaystyle \sum_{n=n_o}^\infty a_n.

The Root Test
Suppose n=noan\displaystyle \sum_{n=n_o}^\infty a_n is a positive series and the limit of the nthn^\text{th} root of the nthn^\text{th} term is ρ=limnann\displaystyle \rho=\lim_{n\to\infty}\sqrt[n]{a_n}.

  1. If ρ<1\rho<1, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is convergent.
  2. If ρ>1\rho>1, then n=noan\displaystyle \sum_{n=n_o}^\infty a_n is divergent.

If ρ=1\rho=1 the Root Test FAILS and says nothing about n=noan\displaystyle \sum_{n=n_o}^\infty a_n.

© 2025 MYMathApps

Supported in part by NSF Grant #1123255